Question

a balanced net ionic equation for the reaction of Pb(NO3)2(aq) with NaI(aq).
A) Pb(NO3)2(aq) + 2 NaI(aq) -> PbI2(s) + 2 NaNO3(aq)
B) Pb2+(aq) + 2 NO3-(aq) + 2 Na+(aq) + 2 I-(aq) -> Pb2+(aq) + 2 I-(aq) + 2 Na+(aq) + 2 NO3-(aq)
C) Pb2+(aq) + 2 NO3-(aq) + 2 Na+(aq) + 2 I-(aq) -> PbI2(s) + 2 Na+(aq) + 2 NO3-(aq)
D) Pb2+(aq) + 2 I-(aq) -> PbI2(s)

Answer

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