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Question
A worldwide personal products manufacturer is working on a new hair care product. In the past, 85 percent of new hair care products introduced by this company have become successful (15 percent have failed). Obviously, the marketing research department plays a large role in the introduction of any new product. Historically, 85 percent of the successful products have a favorable rating from marketing research studies and 20 percent of the unsuccessful products have favorable ratings. For the new hair care product, the marketing unit has issued a favorable rating. What is the probability that the new product will be successful?Answer
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Related questions
Q:
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Q:
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Q:
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Q:
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Q:
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Q:
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Q:
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Q:
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Q:
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A. average
B. median
C. sum
D. difference
Q:
The __________________ is a nonparametric counterpart of a small-sample t test for comparing two independent population locations.
A. Wilcoxon rank sum test
B. Kruskal-Wallis H test
C. Wilcoxon signed ranks test
D. sign test
Q:
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A. reject H0 if rs > .457.
B. reject H0 if rs > .623.
C. reject H0 if rs > .441.
D. reject H0 if rs > .646.
E. reject H0 if rs > .689.
Q:
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B. Wilcoxon rank sum test
C. sign test
D. Kruskal-Wallis test
E. Spearman's rank correlation test
Q:
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A. Wilcoxon signed ranks test
B. Wilcoxon rank sum test
C. sign test
D. Kruskal-Wallis test
E. Spearman's rank correlation test
Q:
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Q:
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Q:
The Wilcoxon signed ranks test is the nonparametric counterpart of the
A. large sample test about a single population mean.
B. two independent samples t test.
C. one-way ANOVA F test.
D. paired difference t test.
E. F test for equality of population variances.
Q:
An assumption of the Wilcoxon rank sum test is that the variances of the two populations are equal.
Q:
Nonparametric tests can be more powerful than the corresponding t or F tests if the population distribution is highly skewed or nonnormal.
Q:
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A. 0 to .0642
B. 0 to .0828
C. 0 to .0812
D. .0129 to .0471
E. 0 to .1324
Q:
How well a process is able to meet the requirements set forth by the process design is called
A. process leeway.
B. quality of conformance.
C. quality of performance.
D. quality of design.
Q:
If the process variability steadily increases, we would observe
A. an alternating pattern of a high value followed by a low value on the R chart.
B. an upward trend on the R chart.
C. a downward trend on the R chart.
D. an increasing gradual funnel pattern on the R chart.
E. a decreasing gradual funnel pattern on the R chart.
Q:
If a company is using an chart for a given process with measurement data, it is generally not important or necessary to use an R chart or s chart.
Q:
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Q:
Control charts are used to reduce common causes of variation.
Q:
A sequence of steadily decreasing points on a control chart is called run down.
Q:
How well the design of the product meets and exceeds the needs and expectations of the customers is called the quality of performance.
Q:
Process leeway is the distance between natural tolerance limits and control limits.
Q:
An chart is a control chart on which individual process measurements are plotted versus time.
Q:
A manufacturer of windows produces one type that has a plastic coating. The specification limits for the plastic coating are 30 and 70. From time to time the plastic coating can become uneven. Therefore, in order to keep the coating as even as possible, thickness measurements are periodically taken at four different locations on the window. 15 subgroups were observed, each consisting of four thickness measurements, with the following results: mean of the means = = 50.05, and average range = 8.85. Calculate the center line for the R chart.
A. 50.05
B. 8.85
C. 2.21
D. 0.59
Q:
A motorcycle manufacturer produces the parts for its vehicles in different locations and transports them to its plant for assembly. To keep the assembly operations running efficiently, it is vital that all parts be within specification limits. One important part used in the assembly is the engine camshaft, and one important quality characteristic is the case hardness depth. Specifications state that the hardness depth must be between 3.0 mm and 6.0 mm. To investigate the process, the quality control engineer selected 25 daily subgroups of n = 5 and measured the hardness depth. The process yielded a mean of the means = 4.50 and an average range = 1.01. Calculate the center line for the X-bar chart.
A. 1.01
B. 4.50
C. 3.49
D. 0.90