Question

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)
According to the equation above, how many grams of aluminum are needed to completely react with 3.83mol of hydrochloric acid?
A) 310 g
B) 46.6 g
C) 34.4 g
D) 3.83 g
E) 103.3 g

Answer

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