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Question
Calculate 
for the reaction below,
2 AgBr(aq) + 2 Hg(l) 2 Ag(s) + Hg2Br2(s)
given the following standard reduction potentials.
Hg2Br2(s) + 2 e- 2 Hg(l) + 2 Br-(aq) E = +0.140 V
AgBr(aq) + e- Ag(s) + Br-(aq) E = +0.071 V
A.-0.211 V
B.-0.069 V
C.+1.97 V
D.+0.069 V
E.+0.211 V
Answer
This answer is hidden. It contains 2 characters.
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