Question

Calculate for the reaction below,
5 Cd(s) + 2 MnO4-(aq) + 16 H+(aq) 5 Cd2+(aq) + 2 Mn2+(aq) + 8 H2O()
given the following standard reduction potentials.
MnO4-(aq) + 8 H+(aq) + 5 e- Mn2+(aq) + 4 H2O() E = +1.52 V
Cd2+(aq) + 2 e- Cd(s) E = -0.40 V
A.-1.12 V
B.+1.04 V
C.+1.92V
D.+5.04 V
E.+8.40 V

Answer

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