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Question
Calculate the enthalpy change (DrH) for the reaction below,
N2(g) + 3 F2(g) 2 NF3(g)
given the bond enthalpies of the reactants and products.
Bond Bond Enthalpy
(kJ/molrxn)
N-N 163
N=N 418
NN 945
F-F 155
N-F 283
A.-288 kJ
B.-1070 kJ
C.-637 kJ
D.+288 kJ
E.+293 kJ
Answer
This answer is hidden. It contains 2 characters.
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