Question

Consider the following reduction potentials:
Cd2+(aq) + 2e- Cd(s); = -0.40 V
Pb2+(aq) + 2e- Pb(s); = -0.13 V
Cu2+(aq) + 2e- Cu(s); = 0.34 V
Br2(l) + 2e- 2Br-(aq); = 1.07 V
Under standard-state conditions, which of the following reactions is spontaneous?
A) Cd2+(aq) + Pb(s)→Cd(s) + Pb2+(aq)
B) Pb2+(aq) + Cu(s)→Pb(s) + Cu2+(aq)
C) 2Br-(aq) + Pb2+(aq)→Br2(l) + Pb(s)
D) 2Br-(aq) + Cu2+(aq)→Br2(l) + Cu(s)
E) Cu2+(aq) + Cd(s)→Cu(s) + Cd2+(aq)

Answer

This answer is hidden. It contains 1 characters.