Question

Consider the following standard reduction potentials:
Mg2+(aq) + 2e- Mg(s); = -2.38 V
V2+(aq) + 2e- V(s); = -1.18 V
Cu2+(aq) + e- Cu+(aq); = 0.15 V
Which of the following reactions will proceed spontaneously from left to right under standard-state conditions?
A) Mg(s) + 2Cu2+(aq)→Mg2+(aq) + 2Cu+(aq)
B) V2+(aq) + 2Cu+(aq)→V(s) + 2Cu2+(aq)
C) Mg2+(aq) + 2Cu+(aq)→2Cu2+(aq) + Mg(s)
D) Mg2+(aq) + V(s)→V2+(aq) + Mg(s)
E) 2Cu2+(aq) + 2Cu+(aq)→Mg2+(aq) + Mg(s)

Answer

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