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Question
Determine the standard enthalpy of formation of Fe2O3(s) given the thermochemical equations below.
Fe(s) + 3 H2O(
) Fe(OH)3(s) + 3/2 H2(g) DrH = +160.9 kJ/mol-rxn
H2(g) + 1/2 O2(g) H2O() DrH = -285.8 kJ/mol-rxn
Fe2O3(s) + 3 H2O() 2 Fe(OH)3(s) DrH = +288.6 kJ/mol-rxn
A.-252.6 kJ/mol-rxn
B.+163.7 kJ/mol-rxn
C.-824.2 kJ/mol-rxn
D.+33.2 kJ/mol-rxn
E.+ 890.6 kJ/mol-rxn
Answer
This answer is hidden. It contains 2 characters.
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