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Question
Ethyl alcohol is produced by the fermentation of glucose, C6H12O6.
C6H12O6(s) -> 2 C2H5OH(l) + 2 CO2(g) 
H = - 69.1 kJ
Given that the enthalpy of formation is -277.7 kJ/mol for C2H5OH(l) and -393.5 kJ/mol for CO2(g), find the enthalpy of formation for C6H12O6.
A) -1411.5 kJ/mol
B) -1273.3 kJ/mol
C) -740.3 kJ/mol
D) -602.1 kJ/mol
Answer
This answer is hidden. It contains 1 characters.
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