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Question
For the reaction 2CH4 (g) + 3 Cl2 (g) -> 2 CHCl3 (l) + 3 H2 (g), 
H = -118.6 kJ.Hf = -134.1 kJ/mol for CHCl3 (l). Find Hf for CH4 (g).
A) -193.4 kJ/mol
B) -74.8 kJ/mol
C) 74.8 kJ/mol
D) 193.4 kJ/mol
Answer
This answer is hidden. It contains 1 characters.
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