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Question
Given that
O(g) + e-→O-(g); 
Hº= -142 kJ
O(g) + 2e-→O2-(g); Hº= 702 kJ
the enthalpy change for the reaction represented by the equation
O-(g) + e-→O2-(g) is
A) 0 kJ.
B) -560 kJ.
C) -844 kJ.
D) 844 kJ.
E) 560 kJ.
Answer
This answer is hidden. It contains 1 characters.
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