Question

Given the following, determine Sat 298 K for one mole of NO(g).
2NO(g) + O2(g) → 2NO2(g); Sº= -146.7 J/K at 298K

SubstanceS(J/(mol K)) at 298 K
NO(g)?
O2(g)205.1
NO2(g)240.0


A) 210.9 J/K
B) -90.85 J/K
C) 421.7 J/K
D) -421.7 J/K
E) +90.85 J/K

Answer

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