Question

Given:
Pb2+(aq) + 2e- Pb(s); = -0.13 V
2H+(aq) + 2e- H2(g); = 0.00 V
NO3-(aq) + 4H+(aq) + 3e- NO(g) + 2H2O(l); = 0.96 V
O2(g) + 4H+(aq) + 4e- 2H2O(l); = 1.23 V
PbO2(s) + SO42-(aq) + 4H+(aq) + 2e- PbSO4(s) + 2H2O(l); =1.69V
Under standard-state conditions, which of the following is the best oxidizing agent?
A) H+
B) Pb2+
C) PbO2
D) O2
E) NO3-

Answer

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