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Question
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?
2 Ca(OH)2(aq) + 2 Cl2(g) -> Ca(OCl)2(aq) + CaCl2(aq) + 2 H2O(l)
A) 0.00197 g
B) 0.00394 g
C) 0.00789 g
D) 0.0507 g
Answer
This answer is hidden. It contains 1 characters.
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