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Question
How many grams of PbCl2 are formed when 25.0 mL of 0.654 M KCl react with Pb(NO3)2?
2KCl(aq) + Pb(NO3) 2(aq) -> 2KNO3(aq) + PbCl2(s)
A) 22.7 g
B) 1.64 g
C) 2.27 g
D) 4.54 g
E) 9.08 g
Answer
This answer is hidden. It contains 1 characters.
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