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Question
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 2.46 atm and 45C in the reaction shown below?
XeF6(s) + 3 H2(g) -> Xe(g) + 6 HF(g)
A) 3.65 g
B) 4.46 g
C) 13.4 g
D) 40.2 g
Answer
This answer is hidden. It contains 1 characters.
Related questions
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