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Question
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45C in the reaction shown below?
XeF6(s) + 3 H2(g) -> Xe(g) + 6 HF(g)
A) 9.58 g
B) 11.7 g
C) 35.2 g
D) 106 g
Answer
This answer is hidden. It contains 1 characters.
Related questions
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B) covalent and basic
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