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Question
How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 2.75 g of Fe2S3 if the percent yield for the reaction is 65.0%?
3 Na2S(aq) + 2 FeCl3(aq) -> Fe2S3(s) + 6 NaCl(aq)
A) 50.9 mL
B) 86.0 mL
C) 102 mL
D) 203 mL
Answer
This answer is hidden. It contains 1 characters.
Related questions
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