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Question
How many mL of 0.246 M Pb(NO3)2 are needed to react with 36.0 mL of 0.322 M KCl ?
2KCl(aq) + Pb(NO3) 2(aq) -> 2KNO3(aq) + PbCl2(s)
A) 36.0 mL
B) 18.0 mL
C) 72.0 mL
D) 47.1 mL
E) 23.6 mL
Answer
This answer is hidden. It contains 1 characters.
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