Question

How many moles of BCl3 are needed to produce 10.0 g of HCl(aq) in the following reaction?
BCl3(g) + 3 H2O(l) -> 3 HCl(aq) + B(OH)3(aq)
A) 0.0914 mol
B) 0.274 mol
C) 0.823 mol
D) 10.9 mol

Answer

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