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Question
Hydrogen iodide undergoes decomposition according to the equation2HI(g)
H2(g) + I2(g)The equilibrium constant Kp at 500 K for this equilibrium is 0.060. Suppose 0.520 mol of HI is placed in a 1.00-L container at 500 K. What is the equilibrium concentration of H2(g)?
(R= 0.0821 L·atm/(K·mol))
A) 0.14 M
B) 0.085 M
C) 4.2 M
D) 0.025 M
E) 0.10 M
Answer
This answer is hidden. It contains 1 characters.
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