Question

If 0.1800 g of impure soda ash (Na2CO3) is titrated with 15.66 mL of 0.1082 M HCl, what is the percent purity of the soda ash?
Na2CO3(aq) + 2 HCl(aq) 2 NaCl(aq) + H2O() + CO2(g)
A.17.96%
B.49.89%
C.50.11%
D.94.13%
E.99.77%

Answer

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