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Question
If the energy of n= 3 is -1.51 eV and that of n= 4 is -0.85 eV in a hydrogen atom, a transition from n= 3 to n= 4 will _______________ a photon with an energy of approximately ______________.
A) emit; 2.36 eV
B) absorb; 0.661 eV
C) emit; 0.661 eV
D) absorb; 2.36 eV
Answer
This answer is hidden. It contains 1 characters.
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