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Question

In order to determine the identity of a particular transition metal (M), a voltaic cell is constructed at 25ºC with the anode consisting of the transition metal as the electrode immersed in a solution of 0.0977 M M(NO3)2, and the cathode consisting of a copper electrode immersed in a 1.00 M Cu(NO3)2 solution. The two half-reactions are as follows:
M(s) M2+(aq) + 2e-
Cu2+(aq) + 2e- Cu(s)
The potential measured across the cell is 0.77 V. What is the identity of the metal M?

Reduction Half-ReactionEº(V)
Cu2+(aq) + 2e- Cu(s)+0.34
Ni2+(aq) + 2e- Ni(s)-0.23
Cd2+(aq) + 2e- Cd(s)-0.40
Zn2+(aq) + 2e- Zn(s)-0.76
Mn2+(aq) + 2e- Mn(s)-1.18

A) Cd
B) Ni
C) Cu
D) Mn
E) Zn

Answer

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