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Question
In the following electrochemical cell, what is the reduction half reaction?
Mn(s) | Mn2+(aq) || Fe3+(aq), Fe2+(aq) | Pt(s)
A) Fe3+(aq) + e-→Fe2+(aq)
B) Fe2+(aq) + e-→Fe3+(aq)
C) Fe2+(aq) + Pt(s) →Fe3+(aq) + e-
D) Mn2+(aq) →Mn(s) + 2e-
E) Mn(s) →Mn2+(aq) + 2e-
Answer
This answer is hidden. It contains 1 characters.
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