Question

Let Ube the potential energy (with the zero at zero displacement) and Kbe the kinetic energy of a simple harmonic oscillator. Uavgand Kavgare the average values over a cycle. Then:
A) Kavg>Uavg
B) Kavg<Uavg
C) Kavg= Uavg
D) K= 0 when U= 0
E) K+ U= 0

Answer

This answer is hidden. It contains 1 characters.