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Question
Nitrogen trifluoride decomposes to form nitrogen and fluorine gases according to the following equation:
2NF3(g) 
N2(g) + 3F2(g)
When 2.12 mol of NF3 is placed in a 5.00-L container and allowed to come to equilibrium at 800 K, the mixture is found to contain 0.0362 mol of N2. What is the value of Kp at this temperature? (R = 0.0821 L·atm·mol-1·K-1)
A) 1.07 x 10-5
B) 1.91 x 10-3
C) 1.78 x 10-3
D) 1.11 x 10-5
E) 4.43 x 10-7
Answer
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