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Question
O2(g) + 4 H+(aq) + 4 e- -> 2 H2O(l) E = +1.23 V
Pb2+(aq) + 2 e- -> Pb(s) E = -0.13 V
2 H2O(l) + 2 e- -> H2(g) + 2 OH-(aq) E = -0.83 V
Based on the half-reactions above, electrolysis of an aqueous solution of Pb(NO3)2 is expected to produce.
A) Pb at the cathode and H2 at the anode.
B) Pb at the cathode and O2 at the anode.
C) H2 at the cathode and Pb at the anode.
D) O2 at the cathode and Pb at the anode.
Answer
This answer is hidden. It contains 1 characters.
Related questions
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