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Question
One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4)3(aq)+6NaOH(aq)→2Rh(OH)3(s)+3Na2SO4(aq)
What mass of sodium hydroxide is required to precipitate 74.0g of rhodium(III) hydroxide from a solution containing excess rhodium(III) sulfate?
A) 6.41 g
B) 57.7 g
C) 19.2 g
D) 222 g
E) 74.0 g
Answer
This answer is hidden. It contains 1 characters.
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