Question

One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4)3(aq)+6NaOH(aq)→2Rh(OH)3(s)+3Na2SO4(aq)
If 0.620g of rhodium(III) hydroxide is produced, what mass of sodium sulfate is also produced?
A) 0.572 g
B) 0.930 g
C) 0.858 g
D) 0.620 g
E) 0.381 g

Answer

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