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Question
One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4)3(aq)+6NaOH(aq)→2Rh(OH)3(s)+3Na2SO4(aq)
What is the theoretical yield of rhodium(III) hydroxide from the reaction of 0.590g of rhodium(III) sulfate with 0.266g of sodium hydroxide?
A) 0.341 g
B) 0.266 g
C) 0.184 g
D) 0.856 g
E) 0.368 g
Answer
This answer is hidden. It contains 1 characters.
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