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Question
One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation:
Rh2(SO4)3(aq)+6NaOH(aq)→2Rh(OH)3(s)+3Na2SO4(aq)
If the reaction of 0.650g of rhodium(III) sulfate with excess sodium hydroxide produces 0.320g of rhodium(III) hydroxide, what is the percent yield?
A) 316 %
B) 158 %
C) 39.5 %
D) 49.2 %
E) 79.0 %
Answer
This answer is hidden. It contains 1 characters.
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