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Question
Oxalic acid can donate two protons to water in successive reactions:
(1) H2C2O4(aq) + H2O(l) 
H3O+(aq) + HC2O4-(aq)
(2) HC2O4-(aq) + H2O(l) H3O+(aq) + C2O42-(aq)
If Kc1 = 5.9 10-2 and Kc2 = 6.4 10-5 at 25C, what is the value of Kc for reaction (3)?
(3) H2C2O4(aq) + 2 H2O(l) 2 H3O+(aq) + C2O42-(aq)
A) 3.8 10-6
B) 1.1 10-3
C) 5.9 10-2
D) 9.2 102
Answer
This answer is hidden. It contains 1 characters.
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