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Question
The coefficient of static friction between a certain cylinder and a horizontal floor is 0.40. If the rotational inertia of the cylinder about its symmetry axis is given by I= (1/2)MR2, then the maximum acceleration the cylinder can have without sliding is:A) 0.1 g
B) 0.2 g
C) 0.4 g
D) 0.8 g
E) 1.0 g
Answer
This answer is hidden. It contains 1 characters.
Related questions
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