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Question
The formula of water, H2O, suggestsA) there is twice as much mass of hydrogen as oxygen in each molecule.
B) there are two oxygen atoms and one hydrogen atom per water molecule.
C) there is twice as much mass of oxygen as of hydrogen in each molecule.
D) there are two hydrogen atoms and one oxygen atom per water molecule.
E) none of these
Answer
This answer is hidden. It contains 1 characters.
Related questions
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E) H2O
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B) The abundance of 7Li is less than 6Li.
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Q:
Which of the following atomic symbols represents an isotope of ?
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Q:
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Q:
The number of protons in a given nucleus determines the
A) mass number.
B) atomic number.
C) number of electrons.
D) number of protons.
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Q:
If the Thomson model of the atom had been correct, Rutherford would have observed
A) alpha particles bouncing off the foil.
B) alpha particles going through the foil with little or no deflection.
C) alpha particles greatly deflected by the metal foil.
D) positive particles formed in the foil.
E) None of the above observations is consistent with the Thomson model of the atom.
Q:
A subatomic particle is
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Q:
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B) CO(g) + H2O(g) CO2(g) + H2(g)
C) CO(g) + 3H2(g) CH4(g) + H2O(g)
D) CaO(s) + CO2(g) CaCO3(s)
E) HBr(g) H2(g) + Br2(l)
Q:
For the reaction 2NO(g) + O2(g) 2NO2(g) at 750ºC, what is the relationship between Kc and Kp?A) Kc= KpB) Kc= Kp x (RT)-1C) Kc= Kp= 1.0D) Kc= Kp x (RT)E) Kc= Kp x (RT)1
Q:
The Ostwald process converts ammonia (NH3) to nitric oxide (NO) by reaction with oxygen in the presence of a catalyst at high temperatures. In a test of the process a reaction vessel is initially charged with 3.90 mol NH3(g) and 4.90 mol O2(g), sealed, and heated at a fixed high temperature. When equilibrium is established the reaction mixture is analyzed and found to contain 2.90 mol NO(g). What is the quantity of NH3(g) in the equilibrium reaction mixture?4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)A) 1.00 mol NH3(g)B) 6.80 mol NH3(g)C) 3.90 mol NH3(g)D) 1.28 mol NH3(g)E) 2.00 mol NH3(g)
Q:
Which of the following represents a dynamic equilibrium?
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Q:
For the hypothetical reaction A → products, the concentration of A was monitored over time. From the following graph, what is the rate constant for the decomposition of A?A) -0.02735 s-1B) 2.3026 s-1C) -2.3026 s-1D) 0.02735 s-1E) 0.01188 s-1
Q:
Which of the following corresponds to the correct equation for the half-life of a first-order reaction?A) B) C) D) E)
Q:
The reaction A → products is first-order in A. If the concentration of A is cut in half, the half-life of the reaction willA) decrease by a factor of 1/2.B) double.C) decrease by a factor of 1/4.D) remain constant.E) quadruple.
Q:
A second-order reaction starts with an initial concentration of 0.100 mol/L of the reactant. If the rate constant is 3.6 x 10-2L/(mol·s), what is the time required to decrease the initial concentration to 0.050 mol/L?A) 280 sB) 420 sC) 19.3 sD) 1.39 sE) 830 s
Q:
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Q:
The radioactive nuclide 63Ni decays by a first-order process via the emission of a beta particle. The 63Ni nuclide has a half-life of 100. years. How long will it take for 71% of 63Ni to decay?
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Q:
The nuclide 96Nb decays by a first-order process with a rate constant of 2.96 x 10-2 h-1. How long will it take for 82.0% of the initial amount of 96Nb to be consumed?A) 33.8 hB) 57.9 hC) 27.7 hD) 6.70 hE) 6.08 h
Q:
The reaction between selenous acid and the iodide ion in acid solution isH2SeO3(aq) + 6I-(aq) + 4H+(aq) → Se(s) + 2I3-(aq) + 3H2O(l)The data in the following table were measured at 0C. Experiment[H2SeO3]0(M)[H+]0(M)[I-]0(M)Initial Rate [mol/(L·s)]11.00 x 10-42.00 x 10-23.00 x 10-25.30 x 10-722.00 x 10-42.00 x 10-23.00 x 10-21.06 x 10-633.00 x 10-44.00 x 10-23.00 x 10-26.36 x 10-643.00 x 10-48.00 x 10-23.00 x 10-22.54 x 10-553.00 x 10-48.00 x 10-26.00 x 10-22.04 x 10-462.00 x 10-42.00 x 10-26.00 x 10-28.48 x 10-6Tripling the initial concentration of H2SeO3while holding the initial concentrations of H+ and I- constant increases the rate of the reaction by a factor ofA) 8.B) 4.C) 3.D) 2.E) 1.
Q:
The reaction between selenous acid and the iodide ion in acid solution isH2SeO3(aq) + 6I-(aq) + 4H+(aq) → Se(s) + 2I3-(aq) + 3H2O(l)The data in the following table were measured at 0C. Experiment[H2SeO3]0(M)[H+]0(M)[I"]0(M)Initial Rate [mol/(L·s)]11.00 x 10-42.00 x 10-23.00 x 10-25.30 x 10-722.00 x 10-42.00 x 10-23.00 x 10-21.06 x 10-633.00 x 10-44.00 x 10-23.00 x 10-26.36 x 10-643.00 x 10-48.00 x 10-23.00 x 10-22.54 x 10-553.00 x 10-48.00 x 10-26.00 x 10-22.04 x 10-462.00 x 10-42.00 x 10-26.00 x 10-28.48 x 10-6What is the rate constant for this reaction?A) 1.5 x 104L5/(mol5·s)B) 1.5 x 1010L5/(mol5·s)C) 4.9 x 105L5/(mol5·s)D) 294 L5/(mol5·s)E) 8.8 L5/(mol5·s)
Q:
For the reaction A + B + C → products, the following initial-rate data were obtained. [A]0(mol/L)[B]0(mol/L)[C]0(mol/L)Initial Rate (mol/(L·s))0.400.400.200.01600.200.400.400.00800.600.100.200.00150.200.100.200.00050.200.200.400.0020What are the reaction orders with respect to A, B, and C, respectively?A) 0, 1, 1B) 1, 2, 1C) 1, 1, 1D) 1, 2, 0E) 0, 2, 1
Q:
Nitrosyl chloride is produced from the reaction of nitrogen monoxide and chlorine:2NO(g) + Cl2(g) → 2NOCl(g)The following initial rates at a given temperature were obtained for the concentrations listed below. ExperimentInitial Rate (mol·L-1·h-1)[NO]0(mol·L-1)[Cl2]0(mol·L-1)12.210.250.25219.890.750.2536.630.250.75From the data, what is the experimental rate law?A) Rate = k[Cl2]B) Rate = k[NO]C) Rate = k[NO][Cl2]2D) Rate = k[NO]2[Cl2]E) Rate = k[NO][Cl2]1/2
Q:
If a reaction is first-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 2, the reaction rate will _____.
A) increase by a factor of 2.
B) remain constant.
C) decrease by a factor of .
D) decrease by a factor of .
E) increase by a factor of 4.
Q:
For a certain first-order reaction with the general form aA → products, the rate is 0.32 M·s-1 when the concentration of the reactant is 0.29M. What is the rate constant for this reaction?A) 0.26 s-1B) 1.1 s-1C) 0.32 s-1D) 3.1 s-1E) 3.8 s-1