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Question
The mean and standard deviations for a process are μ = 90 and σ = 9, respectively. For the variable control chart, a sample size of 16 will be used. Calculate the standard deviation of the sample means.
Answer
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Weight Day
Package 1
Package 2
Package 3
Package 4 Monday
23
22
23
24 Tuesday
23
21
19
21 Wednesday
20
19
20
21 Thursday
18
19
20
19 Friday
18
20
22
20 (a) If he sets an upper control limit of 21 and a lower control limit of 19 around the target value of twenty ounces, the control chart is based on what value of z?
(b) With the UCL and LCL of part a, what do you conclude about this processis it in control?
Answer:
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