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Question
The potential energy of a 0.20-kg particle moving along the x axis is given by
U(x) = (8.0 J/m2)x2 -(2.0 J/m4)x4. When the particle is at x= 1.0 m the magnitude of its acceleration is:
A) 0 m/s2
B) -8 m/s2
C) 8 m/s2
D) -40 m/s2
E) 40 m/s2
Answer
This answer is hidden. It contains 1 characters.
Related questions
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