Question

The reaction: 2 HI -> H2 + I2, is second order and the rate constant at 800 K is 9.70 10-2 M-1 s-1. How long will it take for 8.00 10-2 mol/L of HI to decrease to one-fourth of its initial concentration?
A) 0.619 s
B) 124 s
C) 387 s
D) 429 s

Answer

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