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Question
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.
C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g)
Calculate DfH for propane based on the following standard molar enthalpies of formation.
molecule DfH (kJ/mol-rxn)
CO2(g) -393.5
H2O(g) -241.8
A.-1407.7 kJ/mol-rxn
B.+104.7 kJ/mol-rxn
C.-104.7 kJ/mol-rxn
D.-4190.7 kJ/mol-rxn
E.+1407.7 kJ/mol-rxn
Answer
This answer is hidden. It contains 2 characters.
Related questions
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Q:
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All of the following relationships are true EXCEPT
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Q:
Calculate DrG for the combustion of benzene at 325 K.2 C6H6() + 15 O2(g) 12 CO2(g) + 6 H2O()Species DfH (kJ/mol) S (J/Kmol)C6H6() 49.0 173.3O2(g) 0 205.1CO2(g) -393.5 213.7H2O() -285.8 67.0A.-6386 kJ/mol-rxnB.-6078 kJ/mol-rxnC.-7251 kJ/mol-rxnD.-8611 kJ/mol-rxnE.+1431 kJ/mol-rxn
Q:
If a chemical reaction is exothermic, but not spontaneous, which of the following must be true?
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