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Question
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.
C3H8(g) + 5 O2(g) 3 CO2(g) + 4 H2O(g)
Calculate DfH for propane based on the following standard molar enthalpies of formation.
molecule DfH (kJ/mol-rxn)
CO2(g) -393.5
H2O(g) -241.8
A.-1407.7 kJ/mol-rxn
B.+104.7 kJ/mol-rxn
C.-104.7 kJ/mol-rxn
D.-4190.7 kJ/mol-rxn
E.+1407.7 kJ/mol-rxn
Answer
This answer is hidden. It contains 2 characters.
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