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Question
What is Ka at 25ºC for the following equilibrium?
C6H5NH3+(aq) + H2O(l) 
C6H5NH2(aq) + H3O+(aq)
Kb(C6H5NH2) = 4.2 x10-10at 25ºC.
A) 4.2 x10"4
B) 2.4 x103
C) 4.2 x10-10
D) 4.2 x104
E) 2.4 x10-5
Answer
This answer is hidden. It contains 1 characters.
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