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Question

What is the change in free energy at 298 K when 12.0 mL of 0.344 Mcalcium chloride is combined with 73.7 mL of 0.245 M sodium carbonate? (R= 8.31 J/(K·mol))
Ca2+(aq) + CO32-(aq) → CaCO3(s)

SubstanceGºf(kJ/mol) at 298 K
Ca2+(aq)-553.5
CO32-(aq)-527.9
CaCO3(s)-1128.8

A) -36.0 kJ
B) -2.20 x103kJ
C) -41.3 kJ
D) -47.4 kJ
E) 9.16 x103kJ

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