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Question
What is the equilibrium concentration of amide ion (NH2-) in liquid ammonia at 25ºC? ("am"=dissolvedinammonia)
2NH3(l) 
NH4+(am) + NH2-(am); Kc= 1.8 x 10-24 at 25ºC
A) 2.6 x 10-12M
B) 3.6 x 10-24M
C) 1.3 x 10-12M
D) 1.8 x 10-24M
E) 9.0 x 10-25M
Answer
This answer is hidden. It contains 1 characters.
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