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Question
What is the equilibrium constant expression (Ka) for the acid dissociation of hydrocyanic acid HCN? The equation of interest is
HCN(aq) + H2O(l) 
H3O+(aq) + CN-(aq).
A) Ka = ([H3O+][CN-])/([HCN][H2O])
B) Ka = ([H3O+][CN-])/([HCN])
C) Ka = ([HCN][H2O])/([H3O+][CN-])
D) Ka = ([HCN])/([H3O+][CN-])
Answer
This answer is hidden. It contains 1 characters.
Related questions
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