Question

What is the equilibrium constant expression (Ka) for the acid dissociation of nitrous acid HNO2? The equation of interest is
HNO2(aq) + H2O(l) H3O+(aq) + NO2-(aq).
A) Ka = ([H3O+][NO2-])/([HNO2][H2O])
B) Ka = ([H3O+][NO2-])/([HNO2])
C) Ka = ([HNO2][H2O])/([H3O+][NO2-])
D) Ka = ([HNO2])/([H3O+][NO2-])

Answer

This answer is hidden. It contains 1 characters.