Question

What is the percent ionization of a solution prepared by dissolving 0.0111 mol of chloroacetic acid, (HC2H2O2Cl) in 1.80 L of water? For chloroacetic acid, Ka=1.4x10-3.
A) 0.62 %
B) 100 %
C) 38 %
D) 62 %
E) 0.23 %

Answer

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