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Question
What is the reduction half reaction for the chemical reaction in a basic solution
ClO-(aq) + Cr(OH)4-(aq) -> CrO42-(aq) + Cl-(aq)?
A) ClO-(aq) + 2 H+(aq) + 2e- -> Cl-(aq) + H2O(l)
B) ClO-(aq) + H2O(l) + 2e- -> Cl-(aq) + 2 OH-(aq)
C) Cr(OH)4-(aq) + 4 OH-(aq) -> CrO42-(aq) + 4 H2O(l) + 3e-
D) Cr(OH)4-(aq) -> CrO42-(aq) + 4 H+(aq) + 3e-
Answer
This answer is hidden. It contains 1 characters.
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