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Question
What is the standard enthalpy of formation of liquid butyraldehyde, CH3CH2CH2CHO(l)?
CH3CH2CH2CHO(l) + 
O2(g) →4H2O(l) + 4CO2(g); 
Hº= -2471.8 kJ
| Substance | Hºf(kJ/mol) |
| CO2(g) | -393.5 |
| H2O(l) | -285.8 |
A) -245.4 kJ/mol
B) +245.4 kJ/mol
C) -1792.5 kJ/mol
D) -3151.1 kJ/mol
E) +3151.1 kJ/mol
Answer
This answer is hidden. It contains 1 characters.
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