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Question
What is the standard enthalpy of formation of liquid methylamine (CH3NH2)?
C(s) + O2(g) →CO2(g); 
Hº= -393.5 kJ
2H2O(l) →2H2(g) + O2(g); Hº= 571.6 kJ
N2(g) + O2(g) →NO2(g); Hº= 33.10 kJ
4CH3NH2(l) + 13O2(g) →4CO2(g) + 4NO2(g) + 10H2O(l); Hº= -4110.4 kJ
A) +3899.2 kJ/mol
B) -3899.2 kJ/mol
C) -47.3 kJ/mol
D) +47.3 kJ/mol
E) +3178.4 kJ
Answer
This answer is hidden. It contains 1 characters.
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