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Question
What is the standard enthalpy of formation of liquid n-butanol, CH3CH2CH2CH2OH?
CH3CH2CH2CH2OH(l) + 6O2(g) →4CO2(g) + 5H2O(l); 
Hº= -2675 kJ
| Substance | Hºf(kJ/mol) |
| CO2(g) | -393.5 |
| H2O(l) | -285.8 |
A) -328 kJ
B) +3355 kJ
C) -1996 kJ
D) +328 kJ
E) -3355 kJ
Answer
This answer is hidden. It contains 1 characters.
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